GCE A Level Chemistry H1 Online Mock Test: 2026By admin / January 1, 2026 Uncategorized 5/5 - (1 vote) /30 13 Table of Contents Toggle Report a questionShort ExplanationShort ExplanationShort ExplanationShort ExplanationShort Explanation Report a question What’s wrong with this question? You cannot submit an empty report. Please add some details. GCE A Level Chemistry H1 Online Mock Test: 2026 CHEMISTRY: 8873/01 Paper 1 Multiple Choice: For examination from 2026 SPECIMEN PAPER: 1 hour The total mark for this paper is 30. Each correct answer will score one mark 1 / 30 1. The hydrogen molecule contains a covalent bond. What holds the atoms together in this covalent molecule? A. the electrostatic attraction between the atoms in the molecule B. the electrostatic attraction between the electron of one hydrogen atom and the nucleus of the other hydrogen atom C. the electrostatic attraction between the electrons in the bond pair and the two nuclei D. the energy released in the formation of the covalent bond Short Explanation In a covalent bond (like in H₂), the atoms are held together by electrostatic attraction between the shared pair of electrons and both nuclei. The bonding electrons are attracted to both hydrogen nuclei, creating a stable bond. Options A and B are incomplete descriptions. Option D is incorrect because energy release is a result, not the force holding atoms together. 2 / 30 2. Q2. The actual values of the masses of three sub-atomic particles are shown in the table: Particle Mass (kg) proton 1.673 × 10⁻²⁷ neutron 1.675 × 10⁻²⁷ electron 9.109 × 10⁻³¹ Which nickel ion is predicted to have a mass of 1.038 × 10⁻²⁵ kg from these data? A. ⁵⁸₂₈Ni³⁺ B. ⁶⁰₂₈Ni²⁺ C. ⁶²₂₈Ni²⁺ D. ⁶⁴₂₈Ni³⁺ Short Explanation Mass of an atom ≈ (protons + neutrons) × 1.67 × 10⁻²⁷ kg Electron mass is very small, so we ignore it. Now check: For Ni-62 → total nucleons = 62Mass ≈ 62 × 1.67 × 10⁻²⁷≈ 1.035 × 10⁻²⁵ kg (very close to given 1.038 × 10⁻²⁵) Other options give masses further away. ✔ So, Ni-62²⁺ is the best match. 3 / 30 3. Which statement about 1 mol of a metal is always correct? A. It contains the same number of atoms as 1 mol of hydrogen atoms. B. It contains the same number of atoms as 1/12 mol of ¹²C atoms. C. It has the same mass as 1 mol of hydrogen atoms. D. It is liberated from its ions by 1 mol of electrons. Short Explanation 1 mole of any element always contains Avogadro’s number (6.02 × 10²³) of atoms. So, 1 mol of a metal has the same number of atoms as 1 mol of hydrogen atoms. Why others are wrong: B: 1/12 mol has fewer atoms C: Mass depends on molar mass, not same D: Depends on charge of ion, not always 1 mol electrons ✔ Therefore, A is always correct. 4 / 30 4. Which statement about this structure ice crystal is correct? A. All the bond angles surrounding each oxygen atom are 120°. B. Four electrons from each oxygen atom are involved in forming hydrogen bonds. C. The hydrogen bonds, shown by the dotted line, are stronger than the O–H covalent bonds. D. The open structure of ice causes ice to be denser than water. Short Explanation Each oxygen atom has two lone pairs (4 electrons). These lone pairs are responsible for forming hydrogen bonds with neighboring H atoms. Why others are wrong: A: Bond angle is ~104.5°, not 120° C: Hydrogen bonds are weaker than covalent bonds D: Ice is less dense than water due to open structure ✔ Hence, B is correct. 5 / 30 5. The head of the first type of match, called a ‘lucifer’, contained a mixture of antimony(III) sulfide and potassium chlorate(V). When the match was ‘struck’, the following reaction took place: Sb₂S₃(s) + 3KClO₃(s) → Sb₂O₃(s) + 3KCl(s) + 3SO₂(g) Which element is reduced in the reaction? A. antimony B. chlorine C. oxygen D. sulfur Short Explanation To find reduction, check oxidation state decreases: In KClO₃, chlorine = +5 In KCl, chlorine = −1 So chlorine changes: +5 → −1 → reduction Other changes: Sulfur: −2 → +4 (oxidation) Antimony: remains +3 ✔ Therefore, chlorine is reduced. 6 / 30 6. Use of the data booklet is relevant to this question. The successive ionisation energies, in kJ mol⁻¹, of an element X are given: 870, 1800, 3000, 3600, 5800, 7000, 13200 What is X? A. ₃₃As B. ₄₀Zr C. ₅₂Te D. ₅₃I Short Explanation Look for the big jump in ionisation energy: 870 → 1800 → 3000 → 3600 → 5800 → 7000 → 13200 The biggest jump is after removing 6 electrons: This means X has 6 valence electrons. Elements with 6 valence electrons belong to Group 16. From options: As → Group 15 ❌ Zr → Group 4 ❌ Te → Group 16 ✅ I → Group 17 ❌ ✔ Therefore, X = Tellurium (Te). 7 / 30 7. Synthetic rubber is commonly produced from the monomer buta-1,3-diene. What are the numbers of σ bonds and π bonds present in one molecule of buta-1,3-diene? 6,4 7,4 8,2 9,2 8 / 30 8. Polymerisation of ethene gives poly(ethene). How does the carbon-carbon bond in poly(ethene) compare with that in ethene? A. The carbon-carbon bond is longer and stronger in poly(ethene). B. The carbon-carbon bond is longer and weaker in poly(ethene). C. The carbon-carbon bond is shorter and stronger in poly(ethene). D. The carbon-carbon bond is shorter and weaker in poly(ethene). Short Explanation In ethene (C=C), the carbon-carbon bond is a double bond: shorter stronger In poly(ethene), the double bond opens to form single C–C bonds: longer weaker ✔ Therefore, the C–C bond in poly(ethene) is longer and weaker than in ethene. 9 / 30 9. The elements phosphorus, sulfur and chlorine all exhibit covalent bonding. Their melting points are listed: phosphorus: 44°C sulfur: 115°C chlorine: −101°C What accounts for these differences in melting points? A. the number of bond pairs in the molecules B. the number of electrons in the atoms C. the number of electrons in the molecules D. the number of unpaired electrons in the atoms Short Explanation These substances are simple molecular substances: phosphorus = P₄ sulfur = S₈ chlorine = Cl₂ Their melting points depend on the strength of London dispersion forces between molecules. Key idea: More electrons in a molecule → larger electron cloud Stronger temporary dipole attractions Higher melting point So: S₈ has most electrons → highest mp P₄ intermediate Cl₂ least → lowest mp ✔ Therefore, the difference is due to the number of electrons in the molecules. 10 / 30 10. Which set of bond angles in pyruvic acid [ CH₃–CO–CO₂H ] would be predicted by Valence Shell Electron Pair Repulsion theory? A. 105°, 109°, 120° B. 105°, 120° only C. 109°, 120°, 180° D. 109°, 120° only Short Explanation Pyruvic acid: CH₃–CO–COOH Bond angles present: 1. CH₃ carbon: tetrahedral bond angle ≈ 109° 2. Carbonyl carbon (C=O): trigonal planar bond angle ≈ 120° 3. Carboxylic acid carbon: also trigonal planar ≈ 120° Why others are wrong? 105° is typical for bent molecules like H₂O (due to lone pairs), not here 180° is linear geometry, not present in pyruvic acid ✔ Therefore, only 109° and 120° are present. 11 / 30 11. The gases butane, 2-methylpropane and propane are kept in a sealed container at atmospheric pressure and room temperature. Which row represents the order in which these gases will liquefy as the pressure in the container is gradually increased? A B C D Short Explanation: Liquefaction depends on boiling point: butane (straight chain) → highest boiling point 2-methylpropane (branched) → slightly lower propane → lowest boiling point Higher boiling point gas liquefies first on increasing pressure. ✔ Order: butane → 2-methylpropane → propane 12 / 30 12. Ammonia gas reacts with gaseous hydrogen chloride to form a white smoke of ammonium chloride. Which statements correctly describe the behaviour of ammonia in this reaction? It acts as an Arrhenius acid. It acts as an Arrhenius base. It acts as a Brønsted–Lowry acid. It acts as a Brønsted–Lowry base. A. 1 and 3 B. 2 and 4 C. 3 only D. 4 only Short Explanation Reaction: NH₃ + HCl → NH₄Cl NH₃ accepts H⁺ from HCl So NH₃ acts as a Brønsted–Lowry base Why not Arrhenius base? Arrhenius base produces OH⁻ in aqueous solution Here reaction is in gas phase, so Arrhenius concept does not apply ✔ Therefore, only statement 4 is correct → D 13 / 30 13. Which solution, when added to 25 cm³ of 0.100 mol dm⁻³ NaOH, produces a buffer solution? A. 25 cm³ of 0.075 mol dm⁻³ CH₃CO₂H B. 25 cm³ of 0.100 mol dm⁻³ HCl C. 100 cm³ of 0.050 mol dm⁻³ HCl D. 150 cm³ of 0.025 mol dm⁻³ CH₃CO₂H After reaction: acid left = 0.00125 mol acetate formed = 0.0025 mol Weak acid + conjugate base present → buffer ✔ Therefore, D is correct. 14 / 30 14. The table shows data on two acid-base indicators: Indicator pH range Acid colour Alkali colour bromocresol green 3.8–5.5 yellow blue phenol red 6.8–8.5 yellow red Which conclusion can be drawn about a solution in which: bromocresol green is blue phenol red is yellow weakly acidic it is nutral weakly alkaline strongly alkaline Short Explanation Bromocresol green blue → pH > 5.5 Phenol red yellow → pH < 6.8 So: 5.5<pH<6.8 This is slightly above acidic region / near neutral but on alkaline side. ✔ Therefore, solution is weakly alkaline → C 15 / 30 15. When there is a small increase in the amount of CO₂(g) in the atmosphere, the pH of an ocean is maintained by a series of chemical reactions. Which equation maintains the pH in the ocean? A. CO₂ + H₂O → H₂CO₃ B. H₂CO₃ → H⁺ + HCO₃⁻ C. Ca²⁺ + 2H⁻ → CaH₂ D. H⁺ + CO₃²⁻ → HCO₃⁻ Short Explanation When CO₂ dissolves in ocean water: CO₂ + H₂O ⇌ H₂CO₃ H₂CO₃ ⇌ H⁺ + HCO₃⁻ This increases H⁺, which would lower pH. To resist this change, the ocean uses its carbonate buffer system: H⁺ + CO₃²⁻ → HCO₃⁻ This reaction removes excess H⁺, helping maintain pH. ✔ Therefore, D is the buffering reaction that maintains ocean pH. 16 / 30 16. Q16. Which row describes and explains the trend in electronegativity from fluorine to iodine? A B C D Short Explanation From fluorine to iodine (down Group 17): Atomic radius increases More electron shells are added More shielding occurs So the bonding pair of electrons is farther from the nucleus and feels less attraction. Thus: Electronegativity decreases down the group ✔ Therefore, A is correct. 17 / 30 17. Which diagram represents the change in ionic radius of the ions of the elements across the third period (Na to Cl)? A B C D 18 / 30 18. The diagram represents the Boltzmann distribution of molecular energies of a sample of gas at a given temperature. As temperature increases, which statements are correct? The maximum of the curve is displaced to the right. The proportion of molecules with energies above any given value increases. The proportion of molecules with any given energy increases. A. 1, 2 and 3 B. 1 and 2 only C. 1 only D. 2 and 3 only Short Explanation When temperature increases: ✔ Statement 1: True Peak moves to the right (higher energy) ✔ Statement 2: True More molecules have energy above any chosen activation energy ✘ Statement 3: False The distribution spreads out Some energy values have lower proportion, some higher Not true for any given energy ✔ Therefore, 1 and 2 only are correct → B 19 / 30 19. The conversion of diamond into graphite is slightly exothermic. Diamond does not readily change into graphite. Which reaction pathway diagram correctly represents this conversion? A B C D Short Explanation Given: Slightly exothermic → products have slightly lower energy than reactants Does not readily change → high activation energy So correct graph must show: ✔ Diamond starts at higher energy✔ Graphite ends slightly lower✔ Large hump (high activation energy) Check options: A: graphite higher → wrong B: low activation energy → wrong C: graphite same/higher → wrong D: slight energy drop + large activation energy → correct ✔ Therefore, D is correct. 20 / 30 20. Which statement about the effect of a catalyst on a system at equilibrium is correct? A. It increases the equilibrium constant for the forward reaction. B. It increases the equilibrium yield of product. C. It increases the rate constant equally for both the forward reaction and the reverse reaction. D. It increases the rate constant for the forward reaction, but not that of the reverse reaction. Short Explanation A catalyst: lowers activation energy for both forward and reverse reactions speeds up both reactions equally does not change equilibrium position or Kc ✔ Therefore, C is correct 21 / 30 21. In the reaction between aqueous sodium thiosulfate and dilute acid: first order with respect to [acid] at low concentration zero order with respect to [acid] at high concentration Which graph represents the experimental results? A B C D 22 / 30 22. Q22. The use of catalytic converters in car exhaust systems reduces the amount of harmful nitrogen oxides emitted into the atmosphere. Which statements about the catalytic converter are correct? The catalyst is coated onto a honeycomb surface to provide a smaller surface area to increase the rate of the reaction. The catalyst used is a heterogeneous catalyst which lowers the activation energy for the conversion of NO into N₂. The forces of attraction holding the CO and NO molecules onto the surface of the catalyst are weaker than the forces of attraction holding the product molecules onto the surface. Rhodium can be used as a catalyst in the catalytic converter. A. 1, 2 and 4 B. 1 and 3 C. 2, 3 and 4 D. 2 and 4 only 23 / 30 23. In which reaction will the equilibrium yield of the right-hand product be increased by both of the indicated changes in pressure and temperature? A B C D 24 / 30 24. Iodine trichloride, ICl₃, is made by reacting iodine with chlorine. Given: Find standard enthalpy of formation of solid ICl₃. A (−84 kJ mol⁻¹) B (−74 kJ mol⁻¹) C (−94 kJ mol⁻¹) DB (−54 kJ mol⁻¹) 25 / 30 25. The equation for the complete combustion of ethanethiol is: A 20 cm³ sample of ethanethiol vapour is ignited with 100 cm³ of oxygen. After burning, the gas is cooled to room temperature. The cooled gas is then treated with excess aqueous alkali. What percentage of the final volume of cooled gas dissolves in the alkali? A. 29% B. 57% C. 86% D. 100% 26 / 30 26. What is the skeletal formula for 2,2,3-trimethylpentane? A B C D 27 / 30 27. Which molecular formulae could represent molecules that exhibit cis-trans isomerism? C₃H₆BrI C₃H₅I C₃H₄I₂ C₃H₄BrI A. 1, 2 and 3 B. 2, 3 and 4 C. 2 and 4 only D. 3 and 4 only 28 / 30 28. A B C D 29 / 30 29. A B C D 30 / 30 30. When egg white is heated, protein molecules are denatured. Which statements describe what happens in this process? The hydrogen bonds and induced dipole interactions are broken. The peptide bonds are broken by hydrolysis. The three-dimensional structure of the molecule changes. A. 1 and 2 B. 1 and 3 C. 2 and 3 D. 3 only Your score isThe average score is 54% 0% Restart quiz Post Views: 35
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