Chemical Kinetics Class 12 Chemistry Free Online Mock Test 1By admin / March 12, 2025 Class 12 Chemistry Online Free Mock Test 5/5 - (2 votes) Report a question What’s wrong with this question?You cannot submit an empty report. Please add some details. 🧪Chemical Kinetics – 25 MCQ Quiz🔢 Number of Questions: 25 MCQs ⏱️ Time Required: 20 minutes 📚 Subject: Chemistry (Chemical Kinetics) 🎯 Difficulty Level: Moderate (10+2 / NEET Level)👨🎓 Ideal For: NEET UG aspirants 10+2 Board/NCERT/17+Age Chemistry students Competitive exam learners📌 Key Features: Concept-based questions Covers important periodic trends Helps in quick revision Useful for mock test practice🚀 Outcome: After completing this quiz, you will be able to confidently understand and apply Chemical Kinetics in exams. 1 / 25 1 2 3 4 2 / 25 1 2 3 4 3 / 25 1 2 5/3 0 4 / 25In 30 minutes, a first-order reaction is 50% complete. Calculate the amount of time it took to complete 87.5 percent of the reaction. a) 30 minutes b) 60 minutes c) 90 minutes d) 120 minutes Explanation: In 30 minutes, the reaction is 50% complete. As a result, t1/2 = 30 minutes.In two half-lives, 75% of the process is accomplished. As a result, t = 2 ×30 = 60 minutes.In three half-lives, 87.5 percent of the reaction is finished.Hence, t = 3 × 30 = 90 minutes. 5 / 25In a reaction, what is the driving force? a) Energy given b) Energy released c) Free energy d) None of the mentioned 6 / 25 2 1 1.5 Zero 7 / 25If a reaction’s rate is represented as rate = k [A]² [B], the reaction’s order will be 1 2 3 4 8 / 25A reaction’s rate constant is k=3.28 × 10-4 s-1. Determine the reaction’s order. a) First order b) Second order c) Third order d) Fourth order Answer-:: a)first orderExplanation: Given that k= 3.28 × 10-4s-1The standard formula for calculating rate constant units is k=(mol L-1)1-ns-1, where n is the order of the reaction. For (mol L-1)1-ns-1 to become s-1, the value of n must be 1. As a result, k=3.28 × 10-4s-1 denotes a first order reaction. 9 / 25Dimethyl ether breakdown is a fractional order process. rate =k(PCH3OCH3)3/2 gives the rate. What are the units of rate and rate constant if pressure is measured in bars and time is measured in minutes?(a bar min-1, bar2 min-1(b) bar min-1, bar1/2 min-1(c) bar1/2 min-1, bar² min-1(d) bar min-1, bar1/2 min-1 a b c d 10 / 25The reaction NO2 + CO → NO + CO2 occurs in two steps. Locate the rate law.2NO2 → NO + NO3 (k1) – slowNO3 + CO → CO2 + NO2 (k2) – fasta) R = k1 [NO2] ³b) R = k2 [NO3] [CO]c) R = k1 [NO2]d) R = k1 [NO2]² a b c d Answer: d) R = k1 [NO2]²Explanation: In any reaction, the slowest step is the rate determining step; the overall reaction rate is determined by this step. As a result, the rate determining step is 2NO2= NO + NO3(k1). As a result, the rate rule R= k1[NO2]² . 11 / 25Which of the following reactions is an example of a fractional order reaction?((a) NH4NO2 → N2+ 2H2O(b) NO + O3→ NO2+ O2(c) 2NO + Br2→ 2NOBr(d) CH3CHO → CH4+ CO a b c d 12 / 25The rate constant for the reaction 2H2 + 2NO → 2H2O + N2 with rate = K|H2||NO|², is(a) mol L-1 s-1(b) s-1(c) mol-2 L² s-1(d)mol L-1 a b c d 13 / 25What is the rate law for acid hydrolysis of an ester in aqueous solution, such as CH3COOC2H5?a) k [CH3COOC2H5]b) k [CH3COOC2H5] [H2O]c) k [CH3COOC2H5]²d) k a b c d Explaination-: : Acid hydrolysis of ester, CH3COOC2H5 + H2O → CH3COOH + C2H5OHWhen one reactant is taken in excess of the other, the reaction’s sequence can be changed.Water is present in excess according to the rate law R= k [CH3COOC2H5] [H2O].As a result, R=k [CH3COOC2H5]. 14 / 25If the concentration of material X is doubled and that of Y is halved, how many times will the rate of the elementary reaction 3X + Y = X2Y change?a) r2= 4.5r1b) r2= 5r1c) r2= 2r1d) r2= 4r1 a b c d Answer: d) r2= 4r1Because it is an elementary reaction, the rate law r1= k [A]³[B]The new rate will be r2=k when the concentrations are changedr2= k (2[A])3([B]/2) = 4k[A]³[B]As a result, r2=4r1 15 / 25A reaction’s rate constant is determined by (a) temperature of the reaction (b) extent of the reaction (c) initial concentration of the reactants (d) the time of completion of reaction Answer: (d) the time of completion of reactionExplanation-: The rate of reaction constant is determined by the time taken by the reaction is completed by time taken to completion of the whole reaction. 16 / 25The chemical reaction, 2O3→ 3O2 Proceeds asO3 ⇌ O2+ |O| (fast)|O| + O3 → 2O2 (slow)The rate law expression will be(a) Rate = k [O] [O3](b) Rate = k [O3]² [O2]-1(c) Rate = k [O3]²(d) Rate = k [O2] [O] a b c d 17 / 25For a given rate, the unit of rate and the rate constant are the same. (a) zero order reaction (b) first order reaction (c) second order reaction (d) third order reaction 18 / 25The number of molecules of the reactants involved in a single stage of the reaction indicates (a) the order of the reaction (b) the molecularity of the reaction (c) the rapid step of the reaction mechanism, and (d) the reaction half-life. 19 / 25For a unimolecular reaction, (a) the slowest step’s order and molecularity are both one (b) the reaction’s molecularity can be zero, one, or two; (c) the reaction’s molecularity can only be determined experimentally (d) more than one reacting species are engaged in one step. 20 / 25The overall rate of a reaction is determined by (a) the rate of fastest intermediate step (b) the sum total of the rates of all intermediate steps (c) the average of the rates of all the intermediate steps (d) the rate of slowest intermediate step 21 / 25A first order reaction has a half-life length of 10 minutes. In 100 minutes, what proportion of the response will be completed? ( a) 25% (b) 50% (c) 99.9% (d) 75% 22 / 25For a 30 percent breakdown, a first order reaction takes 40 minutes. What will t1/2 be? (a) 77.7 min (b) 52.5 min (c) 46.2 min (d) 22.7 min 23 / 25The rate constant of a first order reaction is 1.15 10-3s-1. How long will it take to decrease 5 g of this reactant to 3 g? (a) 444 seconds (b) 400 seconds (c) 528 seconds (d) 669 seconds 24 / 25A straight line is drawn when log (a – x) is plotted against time t. This shows that the response is of order (a) zero (b) first (c) second (d) third 25 / 25In a chemical reaction, the activation energy is defined as (a) the difference between the energies of the reactants and products, and (b) the sum of the energies of the reactants and products. (c) the difference between the average energy of reactants and products and the energy of the intermediate complex (d) the difference between the energy of the intermediate complex and the average energy of the reactants Your score isThe average score is 32% 0% Restart quiz Post Views: 120
Solid State Class 12 Chemistry Free Online Mock Test 1Chemistry MCQ Practice Sets, Class 12 Chemistry MCQ Test, Class 12 Chemistry Online Free Mock Test / By admin / October 26, 2024
Solutions Class 12 Chemistry Free Online Mock Test 1Chemistry MCQ Practice Sets, Chemistry MCQ Question Bank, Class 12 Chemistry MCQ Test, Class 12 Chemistry Online Free Mock Test, Class 12 Chemistry Online Free Mock Test For JEE Main, Class 12 Chemistry Online Free Mock Test For NEET / By admin / October 26, 2024
Electrochemistry Online Mock Test Class 12 Chemistry – NEET & JEEClass 12 Chemistry Online Free Mock Test For NEET, Chemistry Mock Test Series, Class 12 Chemistry Online Free Mock Test, Class 12 Chemistry Online Free Mock Test For JEE Main / By Anushka Bhattacharya / October 26, 2024
Coordination Compounds Online Mock Test Class 12 Chemistry – NEET & JEENEET Chemistry MCQ Practice Sets, Class 12 Chemistry Online Free Mock Test, Class 12 Chemistry Online Free Mock Test For JEE Main, Class 12 Chemistry Online Free Mock Test For NEET / By admin / October 30, 2024
Chemistry in Everyday Life Online Mock Test Class 12 ChemistryClass 12 Chemistry Online Free Mock Test / By admin / October 30, 2024
Chemical Kinetics Online Mock Test Class 12 Chemistry – NEET & JEEClass 12 Chemistry Online Free Mock Test For NEET, Chemistry Mock Test Series, Class 12 Chemistry Online Free Mock Test, Class 12 Chemistry Online Free Mock Test For JEE Main / By admin / November 1, 2024