Chemical Thermodynamics: Chemistry Free Online Mock Test 1By admin / January 11, 2025 Uncategorized 5/5 - (1 vote) 0% 0 Report a question What’s wrong with this question? You cannot submit an empty report. Please add some details. 🧪Chemical Thermodynamics – 15 MCQ Quiz 🔢 Number of Questions: 15 MCQs ⏱️ Time Required: 15 minutes 📚 Subject: Chemistry (Chemical Thermodynamics) 🎯 Difficulty Level: Moderate (10+2 / NEET Level) 👨🎓 Ideal For: NEET UG aspirants 10+2 Board/NCERT/17+Age Chemistry students Competitive exam learners 📌 Key Features: Concept-based questions Covers important periodic trends Helps in quick revision Useful for mock test practice 🚀 Outcome: After completing this quiz, you will be able to confidently understand and apply Chemical Thermodynamics in exams. 1 / 17 1. Which of the following always has a negative value? (a) heat of reaction (b) heat of solution (c) heat of combustion (d) heat of formation A B C D 2 / 17 2. A reaction, A + B—>C + D + q is found to have a positive entropy change. The reaction will be (i) possible at high temperature (ii) possible only at low temperature (iii) not possible at any temperature (iv) possible at any temperature 3 / 17 3. The enthalpies of all elements in their standard states are : ‘ (i) unity (ii) zero (iii) < 0 (iv) different for each element i ii iii iv 4 / 17 4. For an endothermic reaction. (a) ∆H is -ve (b) ∆H is +ve (c) ∆H is zero (d) none of these A B C D 5 / 17 5. For the process to occur under adiabatic conditions, the correct condition is: (i) ∆T= 0 (ii) ∆p = 0 (iii) q = 0 (iv) w = 0 i ii iii iv 6 / 17 6. The enthalpy of combustion of methane, graphite and dihydrogen at 298 K are -890.3 KJ mol-1, – 393.5 KJ mol-1 and – 285.8 KJ mol-1 respectively. Enthalpy of formation of CHJg) will be (i) – 74.8 KJ mol-1 (ii) – 52.27 KJ mol-1 (iii) + 74.8 KJ mol-1 (iv) + 52.26 KJ mol-1 i ii iii iv 7 / 17 7. Calculate the standard enthalpy of formation of CH3OH. from the following data in kj mol-1: (i) CH3OH(l) + 3/2 02 (g) ———-> CO2 (g) + 2H20 (l); ∆rH– = – 726kj mol-1 (ii) C(s) + 02(g) —————>C02 (g); ∆cH– = -393 kj mol-1 (iii) H2(g) + 1/202(g) —————->H20 (l); ∆fH– = -286 kj mol-1 – 458 – 239 – 412 – 352 The equation we aim at; C(s) + 2H2(g) + l/202(g) ———> CH3OH (l);∆fH– = ±? … (iv) Multiply eqn. (iii) by 2 and add to eqn. (ii) C(s) + 2H2(g) + 202(g) ————->C02(g) + 2H20(Z) ∆H = – (393 + 522) = – 965 kj moH Subtract eqn. (iv) from eqn. (i) CH3OH(Z) + 3/202(g) ————> C02(y) + 2H20(Z); ∆H = – 726 kj mol-1 Subtract: C(s) + 2H2(y) + l/202(g) ———-> CH3OH(Z); ∆fHe = – 239 kj mol-1 8 / 17 8. Thermodynamics is applicable to (a) macroscopic system only (b) microsopic system only (c) homogeneous system only (d) heterogeneous system only A B C D 9 / 17 9. For a cyclic process, the change in internal energy of the system is (A) always +ve (b) equal to zero (c) always -ve (d) none of the above A B C D 10 / 17 10. Which of the following properties is not a function of state? (a) concentration (b) internal energy (c) enthalpy (d) entropy A B C D 11 / 17 11. The bond energy depends upon (a) size of the atom (b) electronegativity (c) bond length (d) all of the above A B C D 12 / 17 12. In a process, 701 ] of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy for the process? A. 307 J B. 255 J C. 458 J D. 457 J Heat absorbed by the system, q = 701 J Work done by the system = – 394 J Change in internal energy (∆U) = q + w = 701 – 394 = 307 J. 13 / 17 13. The process depicted by the equation. H2O (S) ——> H2O (l) ∆H = +1.43 kcal represents (a) fusion (b) melting (c) evaporation (d) boilirtg A B C D 14 / 17 14. A thermodynamic state junction is a quantity (i) used to determine heat changes (ii) whose value is independent of path (iii) used to determine pressure volume work (iv) whose value depends on temperature only. i ii iii iv 15 / 17 15. Which one is the correct unit for entropy? (a) KJ mol (b)JK mol (c)JK mol-1 (d) KJ mol-1 A B C D 16 / 17 16. An isochoric process takes place at constant (a) temperature (b) pressure (c) volume (d) concentration A B C D 17 / 17 17. Enthalpy of combustion of carbon to carbon dioxide is – 393.5 J mol-1 .Calculate the heat released upon formation of 35.2 g of C02 from carbon and oxygen gas. 354 kj 457 kj 314 kj 458 kj The combustion equation is: C(s) + 02 (g) —–> C02(g); AcH = – 393.5 KJ mol-1 Heat released in the formation of 44g of C02 = 393.5 kj Heat released in the formation of 35.2 g of C02=(393.5 KJ) x (35.2g)/(44g) = 314.8 kj Your score isThe average score is 0% 0% Restart quiz Post Views: 23
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