Coordination Compounds Online Mock Test: NEET PYQBy admin / January 12, 2025 Uncategorized 5/5 - (1 vote) 0% 0 Table of Contents Toggle Report a questionReport a questionReport a questionReport a questionQ.Report a questionQ. Report a question What’s wrong with this question? You cannot submit an empty report. Please add some details. Coordination Compounds NEET PYQ 2024-21 NEET = National Eligibility-cum-Entrance Test No of Questions: 15 MCQs Time: 20 Minutes Practicing questions from a variety of competitive exams is really valuable. For instance, working on these questions can still sharpen your problem-solving abilities and boost your confidence. Many topics overlap, so broader practice often leads to stronger overall performance 1 / 15 1. Ethylene diaminetetraacetate ion is a/an: A. Hexadentate ligand B. Ambidentate ligand C. Monodentate ligand D. Bidentate ligand Explanation:EDTA coordinates through six donor atoms (4 oxygen and 2 nitrogen atoms), so it is a hexadentate ligand. 2 / 15 2. Which of the following is not an ambidentate ligand? [NEET 2024 Re] A. C₂O₄²⁻ B. SCN⁻ C. NO₂⁻ D. CN⁻ Explanation:Oxalate ion (C₂O₄²⁻) is a bidentate ligand, not an ambidentate ligand. SCN⁻, NO₂⁻ and CN⁻ can coordinate through two different atoms, so they are ambidentate ligands. 3 / 15 3. [Mn₂(CO)₁₀] and [Co₂(CO)₈] structures have:A. Metal–Metal linkageB. Terminal CO groupsC. Bridging CO groupsD. Metal in zero oxidation state Choose the correct answer from the options given below: [NEET 2024 Re] A. Only A, B, C B. Only B, C, D C. Only A, C, D D. Only A, B, D Explanation:Both Mn₂(CO)₁₀ and Co₂(CO)₈ contain metal–metal bonds and terminal CO groups. The metals are in zero oxidation state. Mn₂(CO)₁₀ does not contain bridging CO groups, so option D is correct. 4 / 15 4. Match List I with List II. [NEET 2024] Choose the correct answer from the options given below: A. A-II, B-III, C-IV, D-I B. A-I, B-III, C-IV, D-II C. A-I, B-IV, C-III, D-II D. A-II, B-IV, C-III, D-I Explanation:A shows linkage isomerism (NO₂⁻/ONO⁻), B shows ionization isomerism, C shows coordination isomerism, and D shows solvate isomerism. 5 / 15 5. Given below are two statements: [NEET 2024] Statement I: Both [Co(NH₃)₆]³⁺ and [CoF₆]³⁻ complexes are octahedral but differ in their magnetic behaviour. Statement II: [Co(NH₃)₆]³⁺ is diamagnetic whereas [CoF₆]³⁻ is paramagnetic. In the light of the above statements, choose the correct answer from the options given below: A. Both Statement I and Statement II are true B. Both Statement I and Statement II are false C. Statement I is true but Statement II is false D. Statement I is false but Statement II is true Explanation:NH₃ is a stronger field ligand than F⁻. Therefore, [Co(NH₃)₆]³⁺ is low-spin and diamagnetic, while [CoF₆]³⁻ is high-spin and paramagnetic. 6 / 15 6. Given below are two statements: [NEET 2024] Statement I: [Co(NH₃)₆]³⁺ is a homoleptic complex whereas [Co(NH₃)₄Cl₂]⁺ is a heteroleptic complex. Statement II: Complex [Co(NH₃)₆]³⁺ has only one kind of ligand but [Co(NH₃)₄Cl₂]⁺ has more than one kind of ligands. In the light of the above statements, choose the correct answer from the options given below: A. Both Statement I and Statement II are true B. Both Statement I and Statement II are false C. Statement I is true but Statement II is false D. Statement I is false but Statement II is true Explanation:Homoleptic complexes contain only one type of ligand, while heteroleptic complexes contain more than one type of ligand. 7 / 15 7. Homoleptic complex from the following complexes is: [NEET 2023] A. Diamminechloridonitrito-N-platinum (II) B. Pentaamminecarbonatocobalt (III) chloride C. Triamminetriaquachromium (III) chloride D. Potassium trioxalatoaluminate (III) Explanation:A homoleptic complex contains only one type of ligand. In potassium trioxalatoaluminate(III), only oxalato ligands are present. 8 / 15 8. Homoleptic complex from the following complexes is: [NEET 2023] A. Diamminechloridonitrito-N-platinum (II) B. Pentaamminecarbonatocobalt (III) chloride C. Triamminetriaquachromium (III) chloride D. Potassium trioxalatoaluminate (III) Explanation:A homoleptic complex contains only one type of ligand. In potassium trioxalatoaluminate(III), only oxalato ligands are present. 9 / 15 9. Select the element (M) whose trihalides cannot be hydrolysed to produce an ion of the form [M(H₂O)₆]³⁺ [NEET 2023 mpr] A. Ga B. In C. Al D. B Explanation:Boron does not have vacant d-orbitals and cannot form the hexaaqua complex ion [B(H₂O)₆]³⁺. Hence, its trihalides cannot be hydrolysed to produce this ion. 10 / 15 10. Which of the following forms a set of complex and a double salt, respectively? [NEET 2023 mpr] A. CuSO₄·5H₂O and CuCl₂·4NH₃ B. PtCl₂·2NH₃ and PtCl₄·2HCl C. K₂PtCl₂·2NH₃ and KAl(SO₄)₂·12H₂O D. NiCl₂·6H₂O and NiCl₂(H₂O)₄ Explanation:K₂PtCl₂·2NH₃ is a coordination complex, while KAl(SO₄)₂·12H₂O (potash alum) is a double salt. 11 / 15 11. Type of isomerism exhibited by compounds[Cr(H₂O)₆]Cl₃, [Cr(H₂O)₅Cl]Cl₂·H₂O, [Cr(H₂O)₄Cl₂]Cl·2H₂O and the value of coordination number (CN) of central metal ion in all these compounds, respectively is: [NEET 2023 mpr] A. Geometrical isomerism, CN = 2 B. Optical isomerism, CN = 4 C. Ionisation isomerism, CN = 4 D. Solvate isomerism, CN = 6 Explanation:These compounds differ in the number of water molecules inside and outside the coordination sphere, showing solvate (hydrate) isomerism. Chromium has coordination number 6 in all complexes. 12 / 15 12. The IUPAC name of the complex [Ag(H₂O)₂][Ag(CN)₂] is: [NEET 2022] A. Dicyanidosilver(II) diaquaargentate(II) B. Diaquasilver(II) dicyanidoargentate(II) C. Dicyanidosilver(I) diaquaargentate(I) D. Diaquasilver(I) dicyanidoargentate(I) Explanation:Both Ag atoms are in +1 oxidation state. The cation is named first → diaquasilver(I), followed by the anion → dicyanidoargentate(I). 13 / 15 13. The [High to Low] order of energy absorbed which is responsible for the color of complexes [NEET 2022](A) [Ni(H₂O)₂(en)₂]²⁺(B) [Ni(H₂O)₄(en)]²⁺(C) [Ni(en)₃]²⁺ is: A. (A) , (B) , (C) B. (C) , (B) , (A) C. (C) , (A) , (B) D. (B) , (A) , (C) Explanation:Ethylenediamine (en) is a stronger field ligand than H₂O. Greater the number of en ligands, greater is crystal field splitting energy (Δ₀), hence more energy is absorbed. 14 / 15 14. Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). [NEET Re-2022] Assertion (A): The metal-carbon bond in metal carbonyls possesses both σ and π character. Reason (R): The ligand to metal bond is a π bond and metal to ligand bond is a σ bond. In the light of the above statements, choose the most appropriate answer from the options given below: A. (A) is not correct but (R) is correct B. Both (A) and (R) are correct and (R) is the correct explanation of (A) C. Both (A) and (R) are correct but (R) is not the correct explanation of (A) D. (A) is correct but (R) is not correct Explanation:In metal carbonyls, ligand-to-metal donation is a σ bond, while metal-to-ligand back bonding is a π bond. Therefore, the reason statement is incorrect. 15 / 15 15. Ethylene diamine tetraacetate (EDTA) ion is: [NEET 2021] A. Hexadentate ligand with four "O" and two "N" donor atoms B. Unidentate ligand C. Bidentate ligand with two "N" donor atoms D. Tridentate ligand with three "N" donor atoms Explanation:EDTA contains six donor atoms (4 oxygen and 2 nitrogen atoms), so it acts as a hexadentate ligand. Your score isThe average score is 0% 0% Restart quiz …………………………………………… 0% 0 Report a question What’s wrong with this question? You cannot submit an empty report. Please add some details. Coordination Compounds NEET PYQ 2020-16 NEET = National Eligibility-cum-Entrance Test No of Questions: 15 MCQs Time: 20 Minutes Practicing questions from a variety of competitive exams is really valuable. For instance, working on these questions can still sharpen your problem-solving abilities and boost your confidence. Many topics overlap, so broader practice often leads to stronger overall performance 1 / 16 1. Which of the following is the correct order of increasing field strength of ligands to form coordination compounds? (2020) A. SCN⁻ < F⁻ < CN⁻ < C₂O₄²⁻ B. F⁻ < SCN⁻ < C₂O₄²⁻ < CN⁻ C. CN⁻ < C₂O₄²⁻ < SCN⁻ < F⁻ D. SCN⁻ < F⁻ < C₂O₄²⁻ < CN⁻ Explanation: According to spectrochemical series, ligand field strength increases in the order:SCN⁻ < F⁻ < C₂O₄²⁻ < CN⁻. 2 / 16 2. The calculated spin only magnetic moment of Cr²⁺ ion is: (2020) A. 4.90 BM B. 5.92 BM C. 2.84 BM D. 3.87 BM Explanation:Cr²⁺ = 3d⁴ configuration with 4 unpaired electrons.μ = √n(n+2) = √24 ≈ 4.90 BM. 3 / 16 3. What is the correct electronic configuration of the central atom in K₄[Fe(CN)₆] based on crystal field theory? (NEET 2019) A. e⁴t₂² B. t₂⁴eg² C. t₂g⁶eg⁰ D. e³t₂³ Explanation: CN⁻ is a strong field ligand, so Fe²⁺ forms a low-spin octahedral complex. 4 / 16 4. Aluminium chloride in acidified aqueous solution forms a complex 'A', in which hybridisation state of Al is 'B'. What are 'A' and 'B', respectively? A. [Al(H₂O)₆]³⁺, sp³d² B. [Al(H₂O)₄]³⁺, sp³ C. [Al(H₂O)₄]³⁺, dsp² D. [Al(H₂O)₆]³⁺, d²sp³ Explanation:[Al(H₂O)₆]³⁺ is octahedral and shows sp³d² hybridisation. 5 / 16 5. The crystal field stabilisation energy (CFSE) for [CoCl₆]⁴⁻ is 18000 cm⁻¹. The CFSE for [CoCl₄]²⁻ will be: A. 6000 cm⁻¹ B. 16000 cm⁻¹ C. 18000 cm⁻¹ D. 8000 cm⁻¹ Explanation:For tetrahedral complexes, Δt ≈ 4/9 Δ₀.Thus, CFSE decreases compared to octahedral complex. 6 / 16 6. The type of isomerism shown by the complex [CoCl₂(en)₂] is: A. Geometrical isomerism B. Coordination isomerism C. Ionization isomerism D. Linkage isomerism Explanation:[CoCl₂(en)₂] can exist in cis and trans forms, showing geometrical isomerism. 7 / 16 7. The geometry and magnetic behaviour of the complex [Ni(CO)₄] are: A. Square planar geometry and diamagnetic B. Tetrahedral geometry and diamagnetic C. Square planar geometry and paramagnetic D. Tetrahedral geometry and paramagnetic Explanation:CO is a strong field ligand. In [Ni(CO)₄], Ni is in zero oxidation state with paired electrons, making the complex diamagnetic and tetrahedral (sp³ hybridisation). 8 / 16 8. Iron carbonyl, Fe(CO)₅ is: A. Tetranuclear B. Mononuclear C. Trinuclear D. Dinuclear Explanation:Fe(CO)₅ contains only one Fe atom, so it is mononuclear. 9 / 16 9. An example of a sigma bonded organometallic compound is: A. Grignard's reagent B. Ferrocene C. Cobaltocene D. Ruthenocene Explanation:Grignard reagent contains a direct σ bond between carbon and magnesium. 10 / 16 10. The correct order of the stoichiometries of AgCl formed when AgNO₃ in excess is treated with the complexes CoCl₃·6NH₃, CoCl₃·5NH₃, CoCl₃·4NH₃ respectively is: (NEET 2017) A. 3AgCl, 1AgCl, 2AgCl B. 3AgCl, 2AgCl, 1AgCl C. 2AgCl, 3AgCl, 2AgCl D. 1AgCl, 3AgCl, 2AgCl Explanation:Number of ionisable chloride ions decreases as more Cl⁻ enter coordination sphere. 11 / 16 11. Correct increasing order for the wavelengths of absorption in the visible region for the complexes of Co³⁺ is: (NEET 2017) A. [Co(H₂O)₆]³⁺, [Co(en)₃]³⁺, [Co(NH₃)₆]³⁺ B. [Co(H₂O)₆]³⁺, [Co(NH₃)₆]³⁺, [Co(en)₃]³⁺ C. [Co(NH₃)₆]³⁺, [Co(en)₃]³⁺, [Co(H₂O)₆]³⁺ D. [Co(en)₃]³⁺, [Co(NH₃)₆]³⁺, [Co(H₂O)₆]³⁺ Explanation:Stronger ligand → greater Δ₀ → lower wavelength absorbed. 12 / 16 12. Pick out the correct statement with respect to [Mn(CN)₆]³⁻ (NEET 2017) A. It is sp³d² hybridised and tetrahedral B. It is d²sp³ hybridised and octahedral C. It is dsp² hybridised and square planar D. It is sp³d² hybridised and octahedral Explanation:CN⁻ is strong field ligand, producing inner orbital octahedral complex. 13 / 16 13. The correct increasing order of trans-effect of the following species is: (NEET-II 2016) A. NH₃ > CN⁻ > Br⁻ > C₆H₅⁻ B. CN⁻ > C₆H₅⁻ > Br⁻ > NH₃ C. Br⁻ > CN⁻ > NH₃ > C₆H₅⁻ D. CN⁻ > Br⁻ > C₆H₅⁻ > NH₃ Explanation:CN⁻ shows very strong trans effect, while NH₃ has weak trans effect. 14 / 16 14. Jahn-Teller effect is not observed in high spin complexes of: (NEET-II 2016) (WB SLST 2025, PG) A. d⁷ B. d⁸ C. d⁴ D. d⁹ Explanation:High-spin d⁸ configuration is symmetrically filled and does not show Jahn-Teller distortion. Jahn-Teller distortion is usually significant for asymmetrically occupied eg orbitals since they are directed towards the ligands and the energy gain is considerably more. In case of unevenly occupied t2g orbitals, the Jahn-Teller distortion is very weak since the t2g set does not point directly at the ligands and therefore, the energy gain is much less. High spin complexes : 15 / 16 15. Which of the following has longest C–O bond length? (Free C–O bond length in CO is 1.128 Å) (NEET-I 2016) A. [Fe(CO)₄]²⁻ B. [Mn(CO)₆]⁺ C. Ni(CO)₄ D. [Co(CO)₄]⁻ Explanation:Greater back bonding weakens C–O bond and increases bond length. 16 / 16 16. Which of the following has longest C–O bond length? (Free C–O bond length in CO is 1.128 Å) (NEET-I 2016) A. [Fe(CO)₄]²⁻ B. [Mn(CO)₆]⁺ C. Ni(CO)₄ D. [Co(CO)₄]⁻ Explanation:Maximum back bonding occurs in [Fe(CO)₄]²⁻, weakening the C–O bond the most and increasing its bond length. Your score isThe average score is 0% 0% Restart quiz …………………………………………… 0% 0 Report a question What’s wrong with this question? You cannot submit an empty report. Please add some details. Coordination Compounds NEET PYQ 2015-12 NEET = National Eligibility-cum-Entrance Test No of Questions: 15 MCQs Time: 20 Minutes Practicing questions from a variety of competitive exams is really valuable. For instance, working on these questions can still sharpen your problem-solving abilities and boost your confidence. Many topics overlap, so broader practice often leads to stronger overall performance 1 / 15 1. The hybridization involved in complex [Ni(CN)₄]²⁻ is (At. No. Ni = 28) (2015) A. sp³ B. d²sp² C. d²sp³ D. dsp² Explanation:[Ni(CN)₄]²⁻ is a square planar complex with dsp² hybridisation. 2 / 15 2. The hybridization involved in complex [Ni(CN)₄]²⁻ is (At. No. Ni = 28) (2015) A. sp³ B. d²sp² C. d²sp³ D. dsp² Explanation: CN⁻ is a strong field ligand, causing pairing of electrons. Hence [Ni(CN)₄]²⁻ forms a square planar complex with dsp² hybridisation. 3 / 15 3. The name of complex ion, [Fe(CN)₆]³⁻ is: A. Hexacyanitoferrate (III) ion B. Tricyanoferrate (III) ion C. Hexacyanidoferrate (III) ion D. Hexacyanoiron (III) ion Explanation:Anionic complexes use metal name ending “-ferrate”; CN⁻ ligand is named cyanido. 4 / 15 4. The sum of coordination number and oxidation number of metal M in the complex [M(en)₂(C₂O₄)]Cl (where en is ethylenediamine) is: A. 6 B. 7 C. 8 D. 9 Explanation:en is bidentate ×2 = 4, oxalate is bidentate = 2.Coordination number = 6.Oxidation state of M = +3.Sum = 6 + 3 = 9. 5 / 15 5. Number of possible isomers for the complex [Co(en)₂Cl₂]Cl will be: A. 1 B. 3 C. 4 D. 2 Explanation:The complex shows cis-trans geometrical isomerism, and cis form is optically active. Total isomers = 3. 6 / 15 6. Cobalt (III) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at 25°C? A. CoCl₃·5NH₃ B. CoCl₃·6NH₃ C. CoCl₃·3NH₃ D. CoCl₃·4NH₃ Explanation:In CoCl₃·3NH₃, all Cl⁻ ions are inside coordination sphere, so no free chloride ion is available. 7 / 15 7. Among the following complexes the one which shows zero crystal field stabilization energy (CFSE) is: A. [Mn(H₂O)₆]³⁺ B. [Fe(H₂O)₆]³⁺ C. [Co(H₂O)₆]²⁺ D. [Co(H₂O)₆]³⁺ Explanation:Fe³⁺ is d⁵. In weak field H₂O ligand, it forms high-spin d⁵ configuration with CFSE = 0. 8 / 15 8. Which of the following complexes is used as an anticancer agent? A. mer-[Co(NH₃)₃Cl₃] B. cis-[PtCl₂(NH₃)₂] C. cis-K₂[PtCl₂Br₂] D. Na₂CoCl₄ Explanation:cis-[PtCl₂(NH₃)₂] is cisplatin, a well-known anticancer drug. 9 / 15 9. A magnetic moment at 1.73 BM will be shown by one among the following A. TiCl₄ B. [CoCl₆]⁴⁻ C. [Cu(NH₃)₄]²⁺ D. [Ni(CN)₄]²⁻ Explanation:1.73 BM corresponds to one unpaired electron. Cu²⁺ has d⁹ configuration with one unpaired electron. 10 / 15 10. The anion of acetylacetone (acac) forms Co(acac)₃ chelate with Co³⁺. The rings of the chelate are: (Karnataka NEET 2013) A. Five membered B. Four membered C. Six membered D. Three membered Explanation:acac acts as a bidentate ligand and forms a six-membered chelate ring with Co³⁺. 11 / 15 11. The correct IUPAC name for [CrF₂(en)₂]Cl is (Karnataka NEET 2013) A. Chloro difluorido ethylene diaminechromium (III) chloride B. Difluoridobis(ethylenediamine)chromium (III) chloride C. Difluorobis-(ethylenediamine) chromium (III) chloride D. Chlorodifluoridobis(ethylenediamine) chromium (III) Explanation:Ligands are named alphabetically: fluorido before ethylenediamine. 12 / 15 12. Which among the following is a paramagnetic complex?(At. No. Mo = 42, Pt = 78)(Karnataka NEET 2013) A. [Co(NH₃)₆]³⁺ B. [Pt(en)Cl₂] C. [CoBr₄]²⁻ D. Mo(CO)₆ Explanation:Br⁻ is a weak field ligand, so [CoBr₄]²⁻ has unpaired electrons and is paramagnetic. 13 / 15 13. Which is diamagnetic? (Karnataka NEET 2013) A. [CoF₆]³⁻ B. [Ni(CN)₄]²⁻ C. [NiCl₄]²⁻ D. [Fe(CN)₆]³⁻ Explanation:CN⁻ is a strong field ligand causing electron pairing, making the complex diamagnetic. 14 / 15 14. Which one of the following is an outer orbital complex and exhibits paramagnetic behaviour? (2012) A. [Ni(NH₃)₆]²⁺ B. [Zn(NH₃)₆]²⁺ C. [Cr(NH₃)₆]³⁺ D. [Co(NH₃)₆]³⁺ Explanation:[Ni(NH₃)₆]²⁺ is an outer orbital octahedral complex (sp³d²) with unpaired electrons. 15 / 15 15. Red precipitate is obtained when ethanol solution of dimethylglyoxime is added to ammoniacal Ni(II). Which of the following statements is not true? (2012 Mains) A. Red complex has a square planar geometry. B. Complex has symmetrical H-bonding. C. Red complex has a tetrahedral geometry. D. Dimethylglyoxime functions as bidentate ligand. Your score isThe average score is 0% 0% Restart quiz …………………………………………… 0% 0 Report a question What’s wrong with this question? You cannot submit an empty report. Please add some details. Coordination Compounds NEET PYQ 2011-08 NEET = National Eligibility-cum-Entrance Test No of Questions: 15 MCQs Time: 20 Minutes Practicing questions from a variety of competitive exams is really valuable. For instance, working on these questions can still sharpen your problem-solving abilities and boost your confidence. Many topics overlap, so broader practice often leads to stronger overall performance 1 / 15 1. Of the following complex ions, which is diamagnetic in nature? 2011 A. [NiCl₄]²⁻ B. [Ni(CN)₄]²⁻ C. [CuCl₄]²⁻ D. CoF₆ Explanation:CN⁻ is a strong field ligand and causes pairing of electrons in Ni²⁺, making the complex diamagnetic and square planar. 2 / 15 2. The complexes [Co(NH₃)₆][Cr(CN)₆] and [Cr(NH₃)₆][Co(CN)₆] are the examples of which type of isomerism? (2011) A. Linkage isomerism B. Ionization isomerism C. Coordination isomerism D. Geometrical isomerism Explanation:Ligands interchange between cationic and anionic complex ions. 3 / 15 3. The complex [Pt(Py)(NH₃)BrCl] will have how many geometrical isomers? (2011) 3 4 0 2 Explanation:Square planar Pt(II) complex with four different ligands gives three geometrical isomers. Q. 4 / 15 4. The d-electron configurations of Cr²⁺, Mn²⁺, Fe²⁺ and Co²⁺ are d⁴, d⁵, d⁶ and d⁷ respectively. Which one of the following will exhibit minimum paramagnetic behaviour? (2011) A. [Mn(H₂O)₆]²⁺ B. [Fe(H₂O)₆]²⁺ C. [Co(H₂O)₆]²⁺ D. [Cr(H₂O)₆]²⁺ Explanation:Co²⁺ (d⁷) has the minimum number of unpaired electrons among the given high-spin aqua complexes. 5 / 15 5. Which of the following carbonyls will have the strongest C−O bond? (2011 Mains) A. Mn(CO)₆⁺ B. Cr(CO)₆ C. V(CO)₆ D. Fe(CO)₅ Explanation:Less back bonding from metal to CO strengthens the C−O bond. Positive charge decreases back donation. 6 / 15 6. Which of the following complex compounds will exhibit highest paramagnetic behaviour?(At. No. Ti = 22, Cr = 24, Co = 27, Zn = 30) (2011 Mains) A. [Ti(NH₃)₆]³⁺ B. [Cr(NH₃)₆]³⁺ C. [Co(NH₃)₆]³⁺ D. [Zn(NH₃)₆]²⁺ Explanation:Cr³⁺ is d³ and contains three unpaired electrons, giving maximum paramagnetism. 7 / 15 7. Which of the following complex ions is not expected to absorb visible light? (2010) A. [Ni(CN)₄]²⁻ B. [Cr(NH₃)₆]³⁺ C. [Fe(H₂O)₆]²⁺ D. [Ni(H₂O)₆]²⁺ Explanation:It is a low-spin d⁸ square planar complex with no suitable d−d transition in visible region. 8 / 15 8. Crystal field stabilization energy for high spin d⁵ octahedral complex is (2010) A. −1.8Δ₀ B. −1.6Δ₀ + P C. −1.2Δ₀ D. −0.6Δ₀ 9 / 15 9. The existence of two different coloured complexes with the composition [Co(NH₃)₄Cl₂] is due to (2010) A. Linkage isomerism B. Geometrical isomerism C. Coordination isomerism D. Ionization isomerism 10 / 15 10. Which one of the following complexes is not expected to exhibit isomerism? 2010 A. [Ni(NH₃)₄(H₂O)₂]²⁺ B. [Pt(NH₃)₂Cl₂] C. [Ni(NH₃)₂Cl₂] D. [Ni(en)₃]²⁺ 11 / 15 11. Out of TiF₆²⁻, CoF₆³⁻, CuCl₂ and NiCl₄²⁻ the colourless species are(Z of Ti = 22, Co = 27, Cu = 29, Ni = 28) (NEET 2009) A. Cu₂Cl₂ and NiCl₄²⁻ B. TiF₆²⁻ and Cu₂Cl₂ C. CoF₆³⁻ and NiCl₄²⁻ D. TiF₆²⁻ and CoF₆³⁻ 12 / 15 12. Which of the following does not show optical isomerism?(en = ethylenediamine) (2009) A. [Co(NH₃)₃Cl₃]⁰ B. [Co(en)Cl₂(NH₃)₂]⁺ C. [Co(en)₃]³⁺ D. [Co(en)₂Cl₂]⁺ 13 / 15 13. Which of the following complex ions is expected to absorb visible light?(At. no. Zn = 30, Sc = 21, Ti = 22, Cr = 24) (2009) A. [Ti(en)₂(NH₃)₂]⁴⁺ B. [Cr(NH₃)₆]³⁺ C. [Zn(NH₃)₆]²⁺ D. [Sc(H₂O)₃(NH₃)₃]³⁺ 14 / 15 14. Which of the following complexes exhibits the highest paramagnetic behaviour?(Where gly = glycine, en = ethylenediamine and bpy = bipyridyl moieties)(At number Ti = 22, V = 23, Fe = 26, Co = 27) (2008) A. [Co(ox)₂(OH)₂] B. [Ti(NH₃)₆]³⁺ C. [V(gly)₂(OH)₂(NH₃)₂]²⁺ D. [Fe(en)(py)(NH₃)₂]²⁺ 15 / 15 15. In which of the following coordination entities the magnitude of Δ₀ (CFSE in octahedral field) will be maximum?(At. No. Co = 27) (NEET 2008) A. [Co(CN)₆]³⁻ B. [Co(C₂O₄)₃]³⁻ C. [Co(H₂O)₆]³⁺ D. [Co(NH₃)₆]³⁺ Your score isThe average score is 0% 0% Restart quiz …………………………………………… 0% 0 Report a question What’s wrong with this question? You cannot submit an empty report. Please add some details. No of Questions: 66 MCQs Time: 110 Minutes 1 / 66 Ethylene diaminetetraacetate ion is a/an: A. Hexadentate ligand B. Ambidentate ligand C. Monodentate ligand D. Bidentate ligand Explanation:EDTA coordinates through six donor atoms (4 oxygen and 2 nitrogen atoms), so it is a hexadentate ligand. 2 / 66 Which of the following is not an ambidentate ligand? [NEET 2024 Re] A. C₂O₄²⁻ B. SCN⁻ C. NO₂⁻ D. CN⁻ Explanation:Oxalate ion (C₂O₄²⁻) is a bidentate ligand, not an ambidentate ligand. SCN⁻, NO₂⁻ and CN⁻ can coordinate through two different atoms, so they are ambidentate ligands. 3 / 66 [Mn₂(CO)₁₀] and [Co₂(CO)₈] structures have:A. Metal–Metal linkageB. Terminal CO groupsC. Bridging CO groupsD. Metal in zero oxidation state Choose the correct answer from the options given below: [NEET 2024 Re] A. Only A, B, C B. Only B, C, D C. Only A, C, D D. Only A, B, D Explanation:Both Mn₂(CO)₁₀ and Co₂(CO)₈ contain metal–metal bonds and terminal CO groups. The metals are in zero oxidation state. Mn₂(CO)₁₀ does not contain bridging CO groups, so option D is correct. 4 / 66 Match List I with List II. [NEET 2024] Choose the correct answer from the options given below: A. A-II, B-III, C-IV, D-I B. A-I, B-III, C-IV, D-II C. A-I, B-IV, C-III, D-II D. A-II, B-IV, C-III, D-I Explanation:A shows linkage isomerism (NO₂⁻/ONO⁻), B shows ionization isomerism, C shows coordination isomerism, and D shows solvate isomerism. 5 / 66 Given below are two statements: [NEET 2024] Statement I: Both [Co(NH₃)₆]³⁺ and [CoF₆]³⁻ complexes are octahedral but differ in their magnetic behaviour. Statement II: [Co(NH₃)₆]³⁺ is diamagnetic whereas [CoF₆]³⁻ is paramagnetic. In the light of the above statements, choose the correct answer from the options given below: A. Both Statement I and Statement II are true B. Both Statement I and Statement II are false C. Statement I is true but Statement II is false D. Statement I is false but Statement II is true Explanation:NH₃ is a stronger field ligand than F⁻. Therefore, [Co(NH₃)₆]³⁺ is low-spin and diamagnetic, while [CoF₆]³⁻ is high-spin and paramagnetic. 6 / 66 Given below are two statements: [NEET 2024] Statement I: [Co(NH₃)₆]³⁺ is a homoleptic complex whereas [Co(NH₃)₄Cl₂]⁺ is a heteroleptic complex. Statement II: Complex [Co(NH₃)₆]³⁺ has only one kind of ligand but [Co(NH₃)₄Cl₂]⁺ has more than one kind of ligands. In the light of the above statements, choose the correct answer from the options given below: A. Both Statement I and Statement II are true B. Both Statement I and Statement II are false C. Statement I is true but Statement II is false D. Statement I is false but Statement II is true Explanation:Homoleptic complexes contain only one type of ligand, while heteroleptic complexes contain more than one type of ligand. 7 / 66 Homoleptic complex from the following complexes is: [NEET 2023] A. Diamminechloridonitrito-N-platinum (II) B. Pentaamminecarbonatocobalt (III) chloride C. Triamminetriaquachromium (III) chloride D. Potassium trioxalatoaluminate (III) Explanation:A homoleptic complex contains only one type of ligand. In potassium trioxalatoaluminate(III), only oxalato ligands are present. 8 / 66 Homoleptic complex from the following complexes is: [NEET 2023] A. Diamminechloridonitrito-N-platinum (II) B. Pentaamminecarbonatocobalt (III) chloride C. Triamminetriaquachromium (III) chloride D. Potassium trioxalatoaluminate (III) Explanation:A homoleptic complex contains only one type of ligand. In potassium trioxalatoaluminate(III), only oxalato ligands are present. 9 / 66 Select the element (M) whose trihalides cannot be hydrolysed to produce an ion of the form [M(H₂O)₆]³⁺ [NEET 2023 mpr] A. Ga B. In C. Al D. B Explanation:Boron does not have vacant d-orbitals and cannot form the hexaaqua complex ion [B(H₂O)₆]³⁺. Hence, its trihalides cannot be hydrolysed to produce this ion. 10 / 66 Which of the following forms a set of complex and a double salt, respectively? [NEET 2023 mpr] A. CuSO₄·5H₂O and CuCl₂·4NH₃ B. PtCl₂·2NH₃ and PtCl₄·2HCl C. K₂PtCl₂·2NH₃ and KAl(SO₄)₂·12H₂O D. NiCl₂·6H₂O and NiCl₂(H₂O)₄ Explanation:K₂PtCl₂·2NH₃ is a coordination complex, while KAl(SO₄)₂·12H₂O (potash alum) is a double salt. 11 / 66 Type of isomerism exhibited by compounds[Cr(H₂O)₆]Cl₃, [Cr(H₂O)₅Cl]Cl₂·H₂O, [Cr(H₂O)₄Cl₂]Cl·2H₂O and the value of coordination number (CN) of central metal ion in all these compounds, respectively is: [NEET 2023 mpr] A. Geometrical isomerism, CN = 2 B. Optical isomerism, CN = 4 C. Ionisation isomerism, CN = 4 D. Solvate isomerism, CN = 6 Explanation:These compounds differ in the number of water molecules inside and outside the coordination sphere, showing solvate (hydrate) isomerism. Chromium has coordination number 6 in all complexes. 12 / 66 The IUPAC name of the complex [Ag(H₂O)₂][Ag(CN)₂] is: [NEET 2022] A. Dicyanidosilver(II) diaquaargentate(II) B. Diaquasilver(II) dicyanidoargentate(II) C. Dicyanidosilver(I) diaquaargentate(I) D. Diaquasilver(I) dicyanidoargentate(I) Explanation:Both Ag atoms are in +1 oxidation state. The cation is named first → diaquasilver(I), followed by the anion → dicyanidoargentate(I). 13 / 66 The [High to Low] order of energy absorbed which is responsible for the color of complexes [NEET 2022](A) [Ni(H₂O)₂(en)₂]²⁺(B) [Ni(H₂O)₄(en)]²⁺(C) [Ni(en)₃]²⁺ is: A. (A) , (B) , (C) B. (C) , (B) , (A) C. (C) , (A) , (B) D. (B) , (A) , (C) Explanation:Ethylenediamine (en) is a stronger field ligand than H₂O. Greater the number of en ligands, greater is crystal field splitting energy (Δ₀), hence more energy is absorbed. 14 / 66 Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). [NEET Re-2022] Assertion (A): The metal-carbon bond in metal carbonyls possesses both σ and π character. Reason (R): The ligand to metal bond is a π bond and metal to ligand bond is a σ bond. In the light of the above statements, choose the most appropriate answer from the options given below: A. (A) is not correct but (R) is correct B. Both (A) and (R) are correct and (R) is the correct explanation of (A) C. Both (A) and (R) are correct but (R) is not the correct explanation of (A) D. (A) is correct but (R) is not correct Explanation:In metal carbonyls, ligand-to-metal donation is a σ bond, while metal-to-ligand back bonding is a π bond. Therefore, the reason statement is incorrect. 15 / 66 Ethylene diamine tetraacetate (EDTA) ion is: [NEET 2021] A. Hexadentate ligand with four "O" and two "N" donor atoms B. Unidentate ligand C. Bidentate ligand with two "N" donor atoms D. Tridentate ligand with three "N" donor atoms Explanation:EDTA contains six donor atoms (4 oxygen and 2 nitrogen atoms), so it acts as a hexadentate ligand. 16 / 66 Which of the following is the correct order of increasing field strength of ligands to form coordination compounds? (2020) A. SCN⁻ < F⁻ < CN⁻ < C₂O₄²⁻ B. F⁻ < SCN⁻ < C₂O₄²⁻ < CN⁻ C. CN⁻ < C₂O₄²⁻ < SCN⁻ < F⁻ D. SCN⁻ < F⁻ < C₂O₄²⁻ < CN⁻ Explanation: According to spectrochemical series, ligand field strength increases in the order:SCN⁻ < F⁻ < C₂O₄²⁻ < CN⁻. 17 / 66 The calculated spin only magnetic moment of Cr²⁺ ion is: (2020) A. 4.90 BM B. 5.92 BM C. 2.84 BM D. 3.87 BM Explanation:Cr²⁺ = 3d⁴ configuration with 4 unpaired electrons.μ = √n(n+2) = √24 ≈ 4.90 BM. 18 / 66 What is the correct electronic configuration of the central atom in K₄[Fe(CN)₆] based on crystal field theory? (NEET 2019) A. e⁴t₂² B. t₂⁴eg² C. t₂g⁶eg⁰ D. e³t₂³ Explanation: CN⁻ is a strong field ligand, so Fe²⁺ forms a low-spin octahedral complex. 19 / 66 Aluminium chloride in acidified aqueous solution forms a complex 'A', in which hybridisation state of Al is 'B'. What are 'A' and 'B', respectively? A. [Al(H₂O)₆]³⁺, sp³d² B. [Al(H₂O)₄]³⁺, sp³ C. [Al(H₂O)₄]³⁺, dsp² D. [Al(H₂O)₆]³⁺, d²sp³ Explanation:[Al(H₂O)₆]³⁺ is octahedral and shows sp³d² hybridisation. 20 / 66 The crystal field stabilisation energy (CFSE) for [CoCl₆]⁴⁻ is 18000 cm⁻¹. The CFSE for [CoCl₄]²⁻ will be: A. 6000 cm⁻¹ B. 16000 cm⁻¹ C. 18000 cm⁻¹ D. 8000 cm⁻¹ Explanation:For tetrahedral complexes, Δt ≈ 4/9 Δ₀.Thus, CFSE decreases compared to octahedral complex. 21 / 66 The type of isomerism shown by the complex [CoCl₂(en)₂] is: A. Geometrical isomerism B. Coordination isomerism C. Ionization isomerism D. Linkage isomerism Explanation:[CoCl₂(en)₂] can exist in cis and trans forms, showing geometrical isomerism. 22 / 66 The geometry and magnetic behaviour of the complex [Ni(CO)₄] are: A. Square planar geometry and diamagnetic B. Tetrahedral geometry and diamagnetic C. Square planar geometry and paramagnetic D. Tetrahedral geometry and paramagnetic Explanation:CO is a strong field ligand. In [Ni(CO)₄], Ni is in zero oxidation state with paired electrons, making the complex diamagnetic and tetrahedral (sp³ hybridisation). 23 / 66 Iron carbonyl, Fe(CO)₅ is: A. Tetranuclear B. Mononuclear C. Trinuclear D. Dinuclear Explanation:Fe(CO)₅ contains only one Fe atom, so it is mononuclear. 24 / 66 An example of a sigma bonded organometallic compound is: A. Grignard's reagent B. Ferrocene C. Cobaltocene D. Ruthenocene Explanation:Grignard reagent contains a direct σ bond between carbon and magnesium. 25 / 66 The correct order of the stoichiometries of AgCl formed when AgNO₃ in excess is treated with the complexes CoCl₃·6NH₃, CoCl₃·5NH₃, CoCl₃·4NH₃ respectively is: (NEET 2017) A. 3AgCl, 1AgCl, 2AgCl B. 3AgCl, 2AgCl, 1AgCl C. 2AgCl, 3AgCl, 2AgCl D. 1AgCl, 3AgCl, 2AgCl Explanation:Number of ionisable chloride ions decreases as more Cl⁻ enter coordination sphere. 26 / 66 Correct increasing order for the wavelengths of absorption in the visible region for the complexes of Co³⁺ is: (NEET 2017) A. [Co(H₂O)₆]³⁺, [Co(en)₃]³⁺, [Co(NH₃)₆]³⁺ B. [Co(H₂O)₆]³⁺, [Co(NH₃)₆]³⁺, [Co(en)₃]³⁺ C. [Co(NH₃)₆]³⁺, [Co(en)₃]³⁺, [Co(H₂O)₆]³⁺ D. [Co(en)₃]³⁺, [Co(NH₃)₆]³⁺, [Co(H₂O)₆]³⁺ Explanation:Stronger ligand → greater Δ₀ → lower wavelength absorbed. 27 / 66 Pick out the correct statement with respect to [Mn(CN)₆]³⁻ (NEET 2017) A. It is sp³d² hybridised and tetrahedral B. It is d²sp³ hybridised and octahedral C. It is dsp² hybridised and square planar D. It is sp³d² hybridised and octahedral Explanation:CN⁻ is strong field ligand, producing inner orbital octahedral complex. 28 / 66 The correct increasing order of trans-effect of the following species is: (NEET-II 2016) A. NH₃ > CN⁻ > Br⁻ > C₆H₅⁻ B. CN⁻ > C₆H₅⁻ > Br⁻ > NH₃ C. Br⁻ > CN⁻ > NH₃ > C₆H₅⁻ D. CN⁻ > Br⁻ > C₆H₅⁻ > NH₃ Explanation:CN⁻ shows very strong trans effect, while NH₃ has weak trans effect. 29 / 66 Jahn-Teller effect is not observed in high spin complexes of: (NEET-II 2016) (WB SLST 2025, PG) A. d⁷ B. d⁸ C. d⁴ D. d⁹ Explanation:High-spin d⁸ configuration is symmetrically filled and does not show Jahn-Teller distortion. Jahn-Teller distortion is usually significant for asymmetrically occupied eg orbitals since they are directed towards the ligands and the energy gain is considerably more. In case of unevenly occupied t2g orbitals, the Jahn-Teller distortion is very weak since the t2g set does not point directly at the ligands and therefore, the energy gain is much less. High spin complexes : 30 / 66 Which of the following has longest C–O bond length? (Free C–O bond length in CO is 1.128 Å) (NEET-I 2016) A. [Fe(CO)₄]²⁻ B. [Mn(CO)₆]⁺ C. Ni(CO)₄ D. [Co(CO)₄]⁻ Explanation:Greater back bonding weakens C–O bond and increases bond length. 31 / 66 The hybridization involved in complex [Ni(CN)₄]²⁻ is (At. No. Ni = 28) (2015) A. sp³ B. d²sp² C. d²sp³ D. dsp² Explanation:[Ni(CN)₄]²⁻ is a square planar complex with dsp² hybridisation. 32 / 66 Which of the following has longest C–O bond length? (Free C–O bond length in CO is 1.128 Å) (NEET-I 2016) A. [Fe(CO)₄]²⁻ B. [Mn(CO)₆]⁺ C. Ni(CO)₄ D. [Co(CO)₄]⁻ Explanation:Maximum back bonding occurs in [Fe(CO)₄]²⁻, weakening the C–O bond the most and increasing its bond length. 33 / 66 The hybridization involved in complex [Ni(CN)₄]²⁻ is (At. No. Ni = 28) (2015) A. sp³ B. d²sp² C. d²sp³ D. dsp² Explanation: CN⁻ is a strong field ligand, causing pairing of electrons. Hence [Ni(CN)₄]²⁻ forms a square planar complex with dsp² hybridisation. 34 / 66 The name of complex ion, [Fe(CN)₆]³⁻ is: A. Hexacyanitoferrate (III) ion B. Tricyanoferrate (III) ion C. Hexacyanidoferrate (III) ion D. Hexacyanoiron (III) ion Explanation:Anionic complexes use metal name ending “-ferrate”; CN⁻ ligand is named cyanido. 35 / 66 The sum of coordination number and oxidation number of metal M in the complex [M(en)₂(C₂O₄)]Cl (where en is ethylenediamine) is: A. 6 B. 7 C. 8 D. 9 Explanation:en is bidentate ×2 = 4, oxalate is bidentate = 2.Coordination number = 6.Oxidation state of M = +3.Sum = 6 + 3 = 9. 36 / 66 Number of possible isomers for the complex [Co(en)₂Cl₂]Cl will be: A. 1 B. 3 C. 4 D. 2 Explanation:The complex shows cis-trans geometrical isomerism, and cis form is optically active. Total isomers = 3. 37 / 66 Cobalt (III) chloride forms several octahedral complexes with ammonia. Which of the following will not give test for chloride ions with silver nitrate at 25°C? A. CoCl₃·5NH₃ B. CoCl₃·6NH₃ C. CoCl₃·3NH₃ D. CoCl₃·4NH₃ Explanation:In CoCl₃·3NH₃, all Cl⁻ ions are inside coordination sphere, so no free chloride ion is available. 38 / 66 Among the following complexes the one which shows zero crystal field stabilization energy (CFSE) is: A. [Mn(H₂O)₆]³⁺ B. [Fe(H₂O)₆]³⁺ C. [Co(H₂O)₆]²⁺ D. [Co(H₂O)₆]³⁺ Explanation:Fe³⁺ is d⁵. In weak field H₂O ligand, it forms high-spin d⁵ configuration with CFSE = 0. 39 / 66 Which of the following complexes is used as an anticancer agent? A. mer-[Co(NH₃)₃Cl₃] B. cis-[PtCl₂(NH₃)₂] C. cis-K₂[PtCl₂Br₂] D. Na₂CoCl₄ Explanation:cis-[PtCl₂(NH₃)₂] is cisplatin, a well-known anticancer drug. 40 / 66 A magnetic moment at 1.73 BM will be shown by one among the following A. TiCl₄ B. [CoCl₆]⁴⁻ C. [Cu(NH₃)₄]²⁺ D. [Ni(CN)₄]²⁻ Explanation:1.73 BM corresponds to one unpaired electron. Cu²⁺ has d⁹ configuration with one unpaired electron. 41 / 66 The anion of acetylacetone (acac) forms Co(acac)₃ chelate with Co³⁺. The rings of the chelate are: (Karnataka NEET 2013) A. Five membered B. Four membered C. Six membered D. Three membered Explanation:acac acts as a bidentate ligand and forms a six-membered chelate ring with Co³⁺. 42 / 66 The correct IUPAC name for [CrF₂(en)₂]Cl is (Karnataka NEET 2013) A. Chloro difluorido ethylene diaminechromium (III) chloride B. Difluoridobis(ethylenediamine)chromium (III) chloride C. Difluorobis-(ethylenediamine) chromium (III) chloride D. Chlorodifluoridobis(ethylenediamine) chromium (III) Explanation:Ligands are named alphabetically: fluorido before ethylenediamine. 43 / 66 Which among the following is a paramagnetic complex?(At. No. Mo = 42, Pt = 78)(Karnataka NEET 2013) A. [Co(NH₃)₆]³⁺ B. [Pt(en)Cl₂] C. [CoBr₄]²⁻ D. Mo(CO)₆ Explanation:Br⁻ is a weak field ligand, so [CoBr₄]²⁻ has unpaired electrons and is paramagnetic. 44 / 66 Which is diamagnetic? (Karnataka NEET 2013) A. [CoF₆]³⁻ B. [Ni(CN)₄]²⁻ C. [NiCl₄]²⁻ D. [Fe(CN)₆]³⁻ Explanation:CN⁻ is a strong field ligand causing electron pairing, making the complex diamagnetic. 45 / 66 Which one of the following is an outer orbital complex and exhibits paramagnetic behaviour? (2012) A. [Ni(NH₃)₆]²⁺ B. [Zn(NH₃)₆]²⁺ C. [Cr(NH₃)₆]³⁺ D. [Co(NH₃)₆]³⁺ Explanation:[Ni(NH₃)₆]²⁺ is an outer orbital octahedral complex (sp³d²) with unpaired electrons. 46 / 66 Red precipitate is obtained when ethanol solution of dimethylglyoxime is added to ammoniacal Ni(II). Which of the following statements is not true? (2012 Mains) A. Red complex has a square planar geometry. B. Complex has symmetrical H-bonding. C. Red complex has a tetrahedral geometry. D. Dimethylglyoxime functions as bidentate ligand. 47 / 66 Low spin complex of d⁶ cation in an octahedral field will have the following energy (Δ₀ = crystal field splitting energy in an octahedral field, P = Electron pairing energy) (2012 Mains) A. −12/5 Δ₀ + P B. −12/5 Δ₀ + 3P C. −2/5 Δ₀ + 2P D. −2/5 Δ₀ + P Explanation:Low-spin d⁶ octahedral complex has configuration t₂g⁶ and contains three paired electron sets. 48 / 66 Of the following complex ions, which is diamagnetic in nature? 2011 A. [NiCl₄]²⁻ B. [Ni(CN)₄]²⁻ C. [CuCl₄]²⁻ D. CoF₆ Explanation:CN⁻ is a strong field ligand and causes pairing of electrons in Ni²⁺, making the complex diamagnetic and square planar. 49 / 66 The complexes [Co(NH₃)₆][Cr(CN)₆] and [Cr(NH₃)₆][Co(CN)₆] are the examples of which type of isomerism? (2011) A. Linkage isomerism B. Ionization isomerism C. Coordination isomerism D. Geometrical isomerism Explanation:Ligands interchange between cationic and anionic complex ions. 50 / 66 The complex [Pt(Py)(NH₃)BrCl] will have how many geometrical isomers? (2011) 3 4 0 2 Explanation:Square planar Pt(II) complex with four different ligands gives three geometrical isomers. Q. 51 / 66 The d-electron configurations of Cr²⁺, Mn²⁺, Fe²⁺ and Co²⁺ are d⁴, d⁵, d⁶ and d⁷ respectively. Which one of the following will exhibit minimum paramagnetic behaviour? (2011) A. [Mn(H₂O)₆]²⁺ B. [Fe(H₂O)₆]²⁺ C. [Co(H₂O)₆]²⁺ D. [Cr(H₂O)₆]²⁺ Explanation:Co²⁺ (d⁷) has the minimum number of unpaired electrons among the given high-spin aqua complexes. 52 / 66 Which of the following carbonyls will have the strongest C−O bond? (2011 Mains) A. Mn(CO)₆⁺ B. Cr(CO)₆ C. V(CO)₆ D. Fe(CO)₅ Explanation:Less back bonding from metal to CO strengthens the C−O bond. Positive charge decreases back donation. 53 / 66 Which of the following complex compounds will exhibit highest paramagnetic behaviour?(At. No. Ti = 22, Cr = 24, Co = 27, Zn = 30) (2011 Mains) A. [Ti(NH₃)₆]³⁺ B. [Cr(NH₃)₆]³⁺ C. [Co(NH₃)₆]³⁺ D. [Zn(NH₃)₆]²⁺ Explanation:Cr³⁺ is d³ and contains three unpaired electrons, giving maximum paramagnetism. 54 / 66 Which of the following complex ions is not expected to absorb visible light? (2010) A. [Ni(CN)₄]²⁻ B. [Cr(NH₃)₆]³⁺ C. [Fe(H₂O)₆]²⁺ D. [Ni(H₂O)₆]²⁺ Explanation:It is a low-spin d⁸ square planar complex with no suitable d−d transition in visible region. 55 / 66 Crystal field stabilization energy for high spin d⁵ octahedral complex is (2010) A. −1.8Δ₀ B. −1.6Δ₀ + P C. −1.2Δ₀ D. −0.6Δ₀ 56 / 66 The existence of two different coloured complexes with the composition [Co(NH₃)₄Cl₂] is due to (2010) A. Linkage isomerism B. Geometrical isomerism C. Coordination isomerism D. Ionization isomerism 57 / 66 Which one of the following complexes is not expected to exhibit isomerism? 2010 A. [Ni(NH₃)₄(H₂O)₂]²⁺ B. [Pt(NH₃)₂Cl₂] C. [Ni(NH₃)₂Cl₂] D. [Ni(en)₃]²⁺ 58 / 66 Out of TiF₆²⁻, CoF₆³⁻, CuCl₂ and NiCl₄²⁻ the colourless species are(Z of Ti = 22, Co = 27, Cu = 29, Ni = 28) (NEET 2009) A. Cu₂Cl₂ and NiCl₄²⁻ B. TiF₆²⁻ and Cu₂Cl₂ C. CoF₆³⁻ and NiCl₄²⁻ D. TiF₆²⁻ and CoF₆³⁻ 59 / 66 Which of the following does not show optical isomerism?(en = ethylenediamine) (2009) A. [Co(NH₃)₃Cl₃]⁰ B. [Co(en)Cl₂(NH₃)₂]⁺ C. [Co(en)₃]³⁺ D. [Co(en)₂Cl₂]⁺ 60 / 66 Which of the following complex ions is expected to absorb visible light?(At. no. Zn = 30, Sc = 21, Ti = 22, Cr = 24) (2009) A. [Ti(en)₂(NH₃)₂]⁴⁺ B. [Cr(NH₃)₆]³⁺ C. [Zn(NH₃)₆]²⁺ D. [Sc(H₂O)₃(NH₃)₃]³⁺ 61 / 66 Which of the following complexes exhibits the highest paramagnetic behaviour?(Where gly = glycine, en = ethylenediamine and bpy = bipyridyl moieties)(At number Ti = 22, V = 23, Fe = 26, Co = 27) (2008) A. [Co(ox)₂(OH)₂] B. [Ti(NH₃)₆]³⁺ C. [V(gly)₂(OH)₂(NH₃)₂]²⁺ D. [Fe(en)(py)(NH₃)₂]²⁺ 62 / 66 In which of the following coordination entities the magnitude of Δ₀ (CFSE in octahedral field) will be maximum?(At. No. Co = 27) (NEET 2008) A. [Co(CN)₆]³⁻ B. [Co(C₂O₄)₃]³⁻ C. [Co(H₂O)₆]³⁺ D. [Co(NH₃)₆]³⁺ 63 / 66 Which of the following will give a pair of enantiomorphs?(en = NH₂CH₂CH₂NH₂) (NEET 2007) A. [Cr(NH₃)₆][Co(CN)₆] B. [Co(en)₂Cl₂]Cl C. Pt(NH₃)₄[PtCl₆] D. [Co(NH₃)₄Cl₂]NO₂ Either a pair of crystals, molecules or compounds that are mirror images of each other but are not identical, and that rotate the plane of polarised light equally, but in opposite directions arc called as enantiomorphs 64 / 66 The d electron configurations of Cr²⁺, Mn²⁺, Fe²⁺ and Ni²⁺ are 3d⁴, 3d⁵, 3d⁶ and 3d⁸ respectively. Which one of the following aqua complexes will exhibit the minimum paramagnetic behaviour?(At. No. Cr = 24, Mn = 25, Fe = 26, Ni = 28) (AIPMT 2007) A. [Fe(H₂O)₆]²⁺ B. [Ni(H₂O)₆]²⁺ C. [Cr(H₂O)₆]²⁺ D. [Mn(H₂O)₆]²⁺ Explanation: [Ni(H₂O)₆]²⁺ is a d⁸ complex with only two unpaired electrons, so it shows minimum paramagnetic behaviour among the given complexes. 65 / 66 [Cr(H₂O)₆]Cl₃ (At. no. of Cr = 24) has a magnetic moment of 3.83 B.M. The correct distribution of 3d electrons in the chromium of the complex is (AIPMT 2006) A. 3dxy¹, 3dyz¹, 3dz²¹ B. 3d(x²−y²)¹, 3dz²¹, 3dxz¹ C. 3dxy¹, 3d(x²−y²)¹, 3dxz¹ D. 3dxy¹, 3dyz¹, 3dxz¹ Explanation:In [Cr(H₂O)₆]³⁺, chromium is in +3 oxidation state → 3d³ configuration.For an octahedral complex, the three electrons occupy the lower energy t₂g orbitals singly: Hence the electrons are distributed in dxy, dyz and dxz orbitals. 66 / 66 [Co(NH₃)₄(NO₂)₂]Cl exhibits (AIPMT 2006) A. Linkage isomerism, geometrical isomerism and optical isomerism B. Linkage isomerism, ionization isomerism and optical isomerism C. Linkage isomerism, ionization isomerism and geometrical isomerism D. Ionization isomerism, geometrical isomerism and optical isomerism Explanation:NO₂⁻ is an ambidentate ligand, so the complex shows linkage isomerism.Exchange of coordinated NO₂⁻ with Cl⁻ gives ionization isomerism.The octahedral complex also shows cis-trans geometrical isomerism.It does not show optical isomerism. Your score isThe average score is 0% 0% Restart quiz Post Views: 36
[Bengali] Haloalkanes and Haloarenes Online Mock Test 20 MCQ-2 Uncategorized / By admin / May 24, 2024