Solid State Chemistry Online Mock Test: NEET PYQ

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🧪 Solid State Chemistry Mock Test – Complete Practice Guide: Prepare smarter for Competitive Exam with this Solid State Chemistry Mock Test, designed strictly according to the latest NEET exam pattern. This test helps you strengthen key concepts like crystal structures, packing efficiency, defects, unit cells, and coordination numbers.

📌 What you will get:
• Carefully selected Hard MCQs (NEET level)
• Concept-based + calculation-based questions
• Time-bound practice to improve speed & accuracy
• Based on previous year trends and important topics

⚡ This mock test is perfect for revision and self-assessment. It allows you to identify weak areas and improve problem-solving skills under real exam conditions.

🎯 Why attempt this test?
• Boost confidence before Hard Chemistry Exam
• Improve conceptual clarity
• Practice exam-level questions
• Enhance time management

💡 “Consistent practice is the key to cracking Hard Chemistry Exam”

Start your preparation now and move one step closer to your dream medical college 🚀

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Solid State Chemistry NEET PYQ

NEET = National Eligibility-cum-Entrance Test [Solid State chemistry is not currently included in the NEET syllabus]

No of Questions: 35 MCQs

Practicing questions from a variety of competitive exams is really valuable. For instance, working on these questions can still sharpen your problem-solving abilities and boost your confidence. Many topics overlap, so broader practice often leads to stronger overall performance

1 / 35

1. A metal has a fcc lattice. The edge length of the unit cell is 404 pm. The density of the metal is 2.72 g cm⁻³. The molar mass of the metal is: (Nₐ = 6.02 × 10²³ mol⁻¹) (2013 NEET)

A. 27 g mol⁻¹

B. 20 g mol⁻¹

C. 40 g mol⁻¹

D. 30 g mol⁻¹

2 / 35

2. Lithium metal crystallises in a body-centred cubic crystal. If the length of the side of the unit cell of lithium is 351 pm, the atomic radius of lithium will be (2009)

A. 151.8 pm

B. 75.5 pm

C. 300.5 pm

D. 240.8 pm

3 / 35

3. Copper crystallises in a face-centred cubic lattice with a unit cell length of 361 pm. What is the radius of copper atom in pm? (2009)

A. 157

B. 181

C. 108

D. 128

4 / 35

4.

A compound is formed by two elements A and B. The element B forms cubic close packed structure and atoms of A occupy 1/3 of tetrahedral voids. If the formula of the compound is AₓBᵧ, then the value of x + y is [PYQ 2023]

A. 4

B. 3

C. 2

D. 5

5 / 35

5. Copper crystallises in fcc unit cell with cell edge length of 3.608 × 10⁻⁸ cm. The density of copper is 8.92 g cm⁻³. Calculate the atomic mass of copper. [NEET 2022]

A. 63.1 u

B. 31.55 u

C. 60 u

D. 65 u

6 / 35

6. Iron exhibits bcc structure at room temperature. Above 900°C, it transforms to fcc structure. The ratio of density of iron at room temperature to that at 900°C (assuming molar mass and atomic radius of iron remains constant with temperature) is [NEET 2018]

A

B

C

D

7 / 35

7. What fraction of one edge centred octahedral void lies in one unit cell of fcc? [PYQ 2023]

A. 1/3

B. 1/4

C. 1/12

D. 1/2

8 / 35

8. The correct option for the number of body centred unit cells in all 14 types of Bravais lattice unit cells is: [NEET 2021]

7

5

4

3

👉 Short Explanation

Body-centred lattices exist in:

Cubic (bcc)

Tetragonal (bct)

Orthorhombic (body-centred)

👉 Total = 3 crystal systems

✔ Correct Answer: (D) 3

9 / 35

9.

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). [NEET-2022]

Assertion (A): In a particular point defect, an ionic solid is electrically neutral, even if few of its cations are missing from its unit cells.

Reason (R): In an ionic solid, Frenkel defect arises due to dislocation of cation from its lattice site to interstitial site, maintaining overall electrical neutrality.

A. Both (A) and (R) are correct and (R) is the correct explanation of (A)

B. Both (A) and (R) are correct but (R) is not the correct explanation of (A)

C. (A) is correct but (R) is not correct

D. (A) is not correct but (R) is correct

👉 Short Explanation

✔ Assertion (A): Correct
It describes Schottky defect → equal number of cations and anions are missing → electrical neutrality maintained

✔ Reason (R): Correct
It describes Frenkel defect → cation shifts to interstitial site → neutrality maintained

❌ But R does NOT explain A (different defects)

👉 Final Answer: (B)

10 / 35

10. Which is the incorrect statement? [NEET 2017]

A. Density decreases in case of crystals with Schottky defect.

B. NaCl(s) is insulator, silicon is semiconductor, silver is conductor, quartz is piezoelectric crystal.

C. Frenkel defect is favoured in those ionic compounds in which sizes of cation and anions are almost equal.

D. FeO₀.₉₈ has non-stoichiometric metal deficiency defect.

👉 Short Explanation

✔ A: Correct → Schottky defect ⇒ vacancies ⇒ density decreases
✔ B: Correct → all properties सही
❌ C: Incorrect concept → Frenkel defect occurs when cation is much smaller than anion, not equal size
✔ D: Correct → FeO₀.₉₈ shows metal deficiency defect

11 / 35

11. With which one of the following elements silicon should be doped so as to give p-type of semiconductor? (2008)

A. Selenium

B. Boron

C. Germanium

D. Arsenic

👉 Short Explanation

👉 p-type semiconductor is formed by doping with Group 13 elements (trivalent)

Boron (B), Aluminium (Al), Gallium (Ga) → create holes (positive charge carriers)

✔ Among given options, only Boron is trivalent

👉 Correct Answer: (B) Boron

12 / 35

12. If NaCl is doped with 10⁻⁴ mol % of SrCl₂, the concentration of cation vacancies will be (Nₐ = 6.02 × 10²³ mol⁻¹) (2007)

A. 6.02 × 10¹⁶ mol⁻¹

B. 6.02 × 10¹⁷ mol⁻¹

C. 6.02 × 10¹⁴ mol⁻¹

D. 6.02 × 10¹⁵ mol⁻¹

13 / 35

13. An element has a body centred cubic (bcc) structure with a cell edge of 288 pm. The atomic radius is: (NEET 2020)

A

B

C

D

14 / 35

14. A metal crystallises with a face-centred cubic lattice. The edge of the unit cell is 408 pm. The diameter of the metal atom is (2012)

A. 288 pm

B. 408 pm

C. 144 pm

D. 204 pm

15 / 35

15. Formula of nickel oxide with metal deficiency defect in its crystal is Ni₀.₉₈O. The crystal contains Ni²⁺ and Ni³⁺ ions. The fraction of nickel existing as Ni²⁺ ions in the crystal is (Odisha NEET 2019)

A. 0.96

B. 0.04

C. 0.50

D. 0.3

👉 Short Explanation

Let fraction of Ni²⁺ = x
Then fraction of Ni³⁺ = 0.98 − x

Charge balance (O²⁻ = 1):

$\Rightarrow x = 0.94$

✔ Correct Answer: (A) 0.96

16 / 35

16. A solid compound XY has NaCl structure. If the radius of the cation is 100 pm, the radius of the anion (Y) will be (2011 Mains)

A. 275.1 pm

B. 322.5 pm

C. 241.5 pm

D. 165.7 pm

17 / 35

17. The number of octahedral void(s) per atom present in a cubic close- packed structure is (2012)

1

2

3

4

18 / 35

18. The vacant space in bcc lattice unit cell is ( NEET 2015, 2008)

A. 48%

B. 23%

C. 32%

D. 26%

👉 Short Explanation

Packing efficiency of bcc = 68%

Vacant (empty) space =

✔ Correct Answer: (C) 32%

19 / 35

19. AB crystallizes in a body centred cubic lattice with edge length ‘a’ equal to 387 pm. The distance between two oppositely charged ions in the lattice is (2010)

A. 335 pm

B. 250 pm

C. 200 pm

D. 300 pm

20 / 35

20. A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is [NEET 2019]

A. C₄A₃

B. C₂A₃

C. C₃A₂

D. C₃A₄

21 / 35

21.

The correct statement regarding defects in crystalline solids is (2015)

A. Frenkel defects decrease the density of crystalline solids

B. Frenkel defect is a dislocation defect

C. Frenkel defect is found in halides of alkaline metals

D. Schottky defects have no effect on the density of crystalline solids

👉 Short Explanation

A: Wrong → Frenkel defect does NOT change density
B: Correct → Frenkel defect = dislocation of cation to interstitial site
C: Wrong → Alkali halides usually show Schottky defect, not Frenkel
D: Wrong → Schottky defect decreases density

👉 Correct Answer: (B)

22 / 35

22. Structure of a mixed oxide is cubic close packed (c.c.p). The cubic unit cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral voids are occupied by divalent metal A and the octahedral voids are occupied by a monovalent metal B. The formula of the oxide is (2012 Mains)

A. ABO₂

B. A₂BO₂

C. A₂B₃O₄

D. AB₂O₂

23 / 35

23. How are edge length ‘a’ of the unit cell and radius ‘r’ of the sphere related to each other in ccp structure? (Choose correct option for your answer) [NEET 2023]

A. a = 2r

B. a = r/2√2

C. a = 4r/√3

D. a = 2√2 r

👉 Short Explanation

In ccp (fcc) structure, atoms touch along the face diagonal

Face diagonal = √2 a
Also, along face diagonal = 4r

So,

✔ Correct Answer: (D) a = 2√2 r

24 / 35

24. The ionic radii of A⁺ and B⁻ ions are 0.98 × 10⁻¹⁰ m and 1.81 × 10⁻¹⁰ m. The coordination number of each ion in AB is [NEET-I 2016]

8

4

6

2

Short Explanation

Calculate radius ratio:
r+/r−=0.98/1.81 ≈ 0.54
Now using radius ratio rule:
0.414 – 0.732 ⇒ Coordination number = 6 (octahedral)
✔ So, coordination number = 6
👉 Correct Answer: (C)

25 / 35

25. A given metal crystallises out with a cubic structure having edge length of 361 pm. If there are four metal atoms in one unit cell, what is the radius of one atom? (2015 Cancelled)

A. 80 pm

B. 108 pm

C. 40 pm

D. 127 pm

26 / 35

26. Lithium has a bcc structure. Its density is 530 kg m⁻³ and its atomic mass is 6.94 g mol⁻¹. Calculate the edge length of a unit cell of lithium metal. (Nₐ = 6.02 × 10²³ mol⁻¹) [NEET-I 2016]

A. 527 pm

B. 264 pm

C. 154 pm

D. 352 pm

27 / 35

27. Percentage of free space in a body centred cubic unit cell is (2008)

A. 34%

B. 28%

C. 30%

D. 32%

The maximum properties of the available volume which may be filled by hard sphere in simple cubic arrangement is π/6 or 0.52

28 / 35

28. In calcium fluoride, having the fluorite structure, the coordination numbers for calcium ion (Ca²⁺) and fluoride ion (F⁻) are [NEET-II 2016]

A. 4 and 2

B. 6 and 6

C. 8 and 4

D. 4 and 8

👉 Short Explanation

In fluorite structure (CaF₂):

Ca²⁺ forms fcc lattice

F⁻ ions occupy tetrahedral voids

👉 Coordination:

Each Ca²⁺ is surrounded by 8 F⁻ ions → CN = 8

Each F⁻ is surrounded by 4 Ca²⁺ ions → CN = 4

✔ Correct Answer: (C) 8 and 4

29 / 35

29. If a is the length of the side of a cube, the distance between the body centred atom and one corner atom in the cube will be (2014)

A

B

C

D

30 / 35

30.

List – I (Defects)
(a) Frenkel defect
(b) Schottky defect
(c) Vacancy defect
(d) Interstitial defect

List – II (shown by)
(i) non-ionic solids and density of the solid decreases
(ii) non-ionic solids and density of the solid increases
(iii) ionic solids and density of the solid decreases
(iv) ionic solids and density of the solid remains constant

Choose the correct answer from the options given below: [NEET Re-2022]

A. (a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)

B. (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)

C. (a)-(i), (b)-(iii), (c)-(ii), (d)-(iv)

D. (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)

👉 Short Explanation

Frenkel defect → ionic solid, density unchanged ⇒ (iv)

Schottky defect → ionic solid, density decreases ⇒ (iii)

Vacancy defect → non-ionic, density decreases ⇒ (i)

Interstitial defect → non-ionic, density increases ⇒ (ii)

✔ Correct matching ⇒ (A)

31 / 35

31. How many number of tetrahedral voids are formed in 5 mol of a compound having cubic close packed structure? [PYQ 2023]

A. 1.550 × 10²⁴

B. 3.011 × 10²⁵

C. 3.011 × 10²⁴

D. 6.022 × 10²⁴

👉 Short Explanation

In ccp (fcc) structure:

Number of tetrahedral voids = 2 × number of atoms

For 5 mol compound:

Number of atoms =

So, tetrahedral voids =

✔ Correct Answer: (D) 6.022 × 10²⁴

32 / 35

32.

Which of the following statements is not correct? (2008)

A. The number of carbon atoms in a unit cell of diamond is 4

B. The number of Bravais lattices in which a crystal can be categorized is 14

C. The fraction of the total volume occupied by the atoms in a primitive cell is 0.48

D. Molecular solids are generally volatile

👉 Short Explanation

✔ A: Correct → Diamond unit cell effectively contains 4 atoms

✔ B: Correct → Total 14 Bravais lattices

❌ C: Incorrect → Packing fraction of simple cubic = 0.52 (52%), not 0.48

✔ D: Correct → Molecular solids are volatile (weak intermolecular forces)

👉 Correct Answer: (C)

33 / 35

33. If a stands for the edge length of the cubic systems: simple cubic, body centred cubic and face centred cubic, then the ratio of radii of the spheres in these systems will respectively (2008)

A

B

C

D

34 / 35

34. What fraction of Fe exists as Fe(III) in Fe₀.₉₆O? (Consider Fe₀.₉₆O to be made up of Fe(II) and Fe(III) only) [NEET Re-2022]

A. 1/20

B. 1/12

C. 0.08

D. 1/16

👉 Short Explanation

Let total Fe = 0.96 mol, O = 1 mol

Let Fe²⁺ = x
Then Fe³⁺ = (0.96 − x)

Charge balance:

$\Rightarrow x = 0.88$

So, Fe³⁺ = 0.96 − 0.88 = 0.08

Fraction of Fe³⁺ =

✔ Correct Answer: (B) 1/12

35 / 35

35. The number of carbon atoms per unit cell of diamond unit cell is (2013 NEET)

6

4

5

8

Diamond is like ZnS (Zinc blende).Carbon forming cep (fcc) and also occupying half of tetrahedral voids.

Total no. of carbon atoms per unit cell =

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